Calderone

Guys if i have a 350 bored at .60 it isnt a 350 anymore am i right ?
what is the formula to calculate my displacement after i bored the engine ?
Thanks

ViciousZ

iTrader: (1)

On a normal 350 the bore is 4.000" and the stroke is 3.48". To convert the bore diameter to radius, divide by 2. The volume of each cylinder is stroke*3.14*(bore/2)^2.
So 3.48*3.14*(4.000/2)^2=43.73 Then multiply by 8 for all 8 cylinders. It makes about 349.8.
So for a 350 bored .060 over, the diameter changes to 4.060.
8*3.48*3.14*(4.060/2)^2=360.4
You got a 360 now.

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91 Z28
Come see The Vicious...

GOLD85

now that your question is answered, i have one, y did u bore your block .60 over. a stadard block doesnt have thick enough walls to do this. at high RPM your piston will be pretty unstable

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when the green flag drops the bull$hit stops

Gold 85 Camaro with no motor, pulled the 2.8 to make way for a 350 wich was pulled this summer because a 406 will replace it. The 406 sports a stock bottom end with ARP bolt holding it togeter, flat top hyper pistons. Comp 282 solid cam(.528 lift with 1.6 rockers) Savin up for my Sportsmen 2 heads right now. still Have the perf RPM and 650 DP i used on the 350. Headers and 3inch exhust. Shooten for mid to low 12s next summer

Vader

If you have MS Excel or Quattro Pro, this sheet has all the calculations you're asking for:

Engine Calculations

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Later,
Vader
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If you want to beat the World, it might reach up and pull you down...
Adobe Acrobat Reader

Xenodrgn

Vicious... thats one hacked formula... interesting nonetheless. Another way to look at it is:

bore diameter ^2 * length of stroke * number of cylinders * .7854 (constant) = CI

make the measurements in centimeters and you come out with CC's...

Hey, to each his own.

five7kid

iTrader: (14)

My Visor doesn't have 0.78539816339745 loaded in it (Pi divided by 4), but it does have 3.1415926535898 "constantly" at my disposal...

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82 Berlinetta, orig V-6 car, now w/86 LG4/TH700R4 (restalled TC). Ported World 305 heads, Crane PowerMax cam. ZZ4 intake, oil pump, pan & baffle. Accel HEI SuperCoil & module. Hooker 2055 headers, 3" Catco cat & 3" catback w/dual-opposite Flowmaster. 2.93 limited slip, Spohn SFCs. AMSOIL syn lubes bumper-to-bumper. Daily year-round driver. Best ET, speed TBD...
57 Bel Air, my 1st car. '66 396, 9.7:1 forged TRWs, Weiand Action+, Holley 750VS w/4150 conversion, GK 270 cam, Magnum rockers, Jacobs Omnipack, 1-3/4" Hedders & 3" Warlocks, TH400 w/TCI Sat Night Special conv & Trans-Scat shift kit, MegaShifter, 3.08 8.2" 10-bolt w/Powertrax, AMSOIL syn lubes bumper-to-bumper. Idles smooth @ 700 RPM in D. Best 15.02/95.06 @ 5800' Bandimere (corrected 13.93/102.4 @ sea level).

RICH92RS350

I hope you mean that it's bored 0.060" and not 0.600"!If it's really been bored .60 then you can probably see daylight through the cylinder wall, if you're not already into the water jacket.
-Rich-

ViciousZ

iTrader: (1)

Xenodrgn, I basically pulled that equation out my butt using common sense (mathematical genius that I am, yeah, right). But my reasoning here was that the area of a circle is pi*r^2. So that's why I divided the diameter by 2 and multiplied by pi. Instead you multiplied the diameter by .7854 which is the same as 3.1416/4 or pi/(2^2). Just trying to explain myself here. Both equations work, but I must admit, yours looks much simpler.

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91 Z28
Come see The Vicious...

Grim Reaper

Actually, both ViciousZ and Xenodgrn's formulas are the same. As Vicious pointed out, Pi*R^2 = D^2*Pi/4. The Constant given by Xenodgrn is just Pi/4 to compensate for use D^2 instead of R^2, as pointed out by ViciousZ.

I should point out the Pi*R^2 is the more "commonly" used formula for calculating Area rather than D^2*Pi/4. You both pass the math test.

[This message has been edited by Glenn91L98GTA (edited November 09, 2001).]

AJ_92RS

The easiest formula I've found is in the back of my PAW catalog.

bore * bore * stroke * .7854 = "X"

"X" * no. of cylinders = total displacement.



That's the formula us folk 'round here use.

AJ